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A coin is tossed n times. The probabilit...

A coin is tossed n times. The probability of getting head atleast once is greater than 0.8. Then the least value of such n is

A

2

B

3

C

4

D

5

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The correct Answer is:
To solve the problem, we need to find the least value of \( n \) such that the probability of getting at least one head when a coin is tossed \( n \) times is greater than 0.8. ### Step-by-Step Solution: 1. **Understanding the Probability of Getting at Least One Head**: The probability of getting at least one head when tossing a coin \( n \) times can be calculated using the complement rule. The complement of getting at least one head is getting all tails. Therefore, we can express this as: \[ P(\text{at least one head}) = 1 - P(\text{all tails}) \] 2. **Calculating the Probability of All Tails**: When a coin is tossed \( n \) times, the probability of getting tails in each toss is \( \frac{1}{2} \). Thus, the probability of getting all tails in \( n \) tosses is: \[ P(\text{all tails}) = \left(\frac{1}{2}\right)^n \] 3. **Setting Up the Inequality**: We want the probability of getting at least one head to be greater than 0.8: \[ 1 - \left(\frac{1}{2}\right)^n > 0.8 \] 4. **Rearranging the Inequality**: Rearranging the inequality gives: \[ \left(\frac{1}{2}\right)^n < 0.2 \] 5. **Expressing 0.2 as a Fraction**: We can express 0.2 as: \[ 0.2 = \frac{1}{5} \] So the inequality becomes: \[ \left(\frac{1}{2}\right)^n < \frac{1}{5} \] 6. **Finding the Least Value of \( n \)**: To find the least value of \( n \), we can test integer values of \( n \): - For \( n = 1 \): \[ \left(\frac{1}{2}\right)^1 = \frac{1}{2} \quad (\text{not less than } \frac{1}{5}) \] - For \( n = 2 \): \[ \left(\frac{1}{2}\right)^2 = \frac{1}{4} \quad (\text{not less than } \frac{1}{5}) \] - For \( n = 3 \): \[ \left(\frac{1}{2}\right)^3 = \frac{1}{8} \quad (\text{is less than } \frac{1}{5}) \] Therefore, the least value of \( n \) that satisfies the condition is \( n = 3 \). ### Final Answer: The least value of \( n \) such that the probability of getting at least one head is greater than 0.8 is \( n = 3 \).
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