The parameters of two small identical current-carrying coils are as follows: the radius of winding is 20 mm, the number of turns is `10^3,` the current is 0.5 A. the distance between the coils is 300 mm. What is the force of interaction between the coils?

Answer

`2.9 xx 10^(-5)N`

Explanation

Making use of the result of the previous problem, we obtain `-(6mu_(0) w^2 i^2 S^2)/(4pi r^4)=-(3pi mu_(0) w^2 i^2 a^4)/(2r^4)`