Calculate the Hall constant for silver knowing its density and atomic mass.

Answer

`1.07xx10^(-10)m^(3)//C`

Explanation

Since silver is a monovalent element, the electron concentration in it is equal to the concentration of atoms. The density is `rho=m_(0)n` where `m_(0)` is the mass of the atom. But `m_(0)=A//N_(A)`, where A is the atomic mass. Hence `n=rhoN_(A)//A` and the Hall constant is `R_(H)=A//erhoN_(A)`