A particle with a mass of 0.2 kg moves according to the law
`s=0.08cos(20pit+(pi)/(4))`
Find the velocity of the particle, its acceleration and the acting force, as well as the amplitudes of the respective quantities.

Answer

`v=1.6picos(20pit+(3pi)/(4));a=32pi^(2)cos(20pit+(5pi)/(4));F=6.4pi^(2)cos(20pit+(5pi)/(4));5.0m//s;3.2xx10^(2)m//s^(2);64N`