Mercury fills a glass tube Fig. so that the total column is 20 cm long. The tube is then rocked, so that the mercury begins to oscillate. Find the frequency and the period of the vibrations.

Answer

`1.6Hz;0.63s.`

Explanation

AS may be seen from Fig the force which restores the body to its equilibrium positions is `F=rhogDeltaV=2rhogSx`. Since this force is proportional to the displacement, the natural frequency of the vibrations can be found from the formula `omega_(0)=sqrt(k//m)`. Here `k=F//x=2rhogS,m=rhoSl`.
Hence `omega_(0)=sqrt(2g//l)`