The period of a pendulum whose suspension is stationary relative to the Earth's surface is 1.50 s. What will its period be, if it is placed in a car moving horizontally with an acceleration of `4.9 m//s^(2)`? What will be the change in the pendulum's angle of equilibrium?

Answer

`1.42 s;26^(@)36`

Explanation

One should find the total acceleration with respect to the Earth: `w=sqrt(a^(2)+g^(2))`. Then the period of the pendulum will be `T=2pisqrt(l//w)`.
The equilibrium position will be deflected from the vertical by an angle `varphi=arc tan""(a)/(g)`