Find the probability of an electron tunneling through a 5Å wide and 0.4 eV high potential barrier, if it is accelerated by a field of 0.3 V

Answer

`w=e^(-1.6)=0.2=20%`.

Explanation

The probability of tunnelling through a potential barrier is
`w=D//D_(0)=e^(-a),"where "a=(2L)/hsqrt(2m(U_(0)-ePhi))`