Find the energy liberated in the course of the thermonuclear reaction
`""_(3)Li^(6)+""_(1)H^(2)to2""_(2)He^(4)`
Do the calculations for one nucleus and for one nucleon. Compare with the energy liberated in the process of fission of uranium.

Answer

22.4 MeV; 2.8 MeV per nucleon.

Explanation

The energy released is found from the masses equation :
`Deltaepsi=(6.01513+2.01410-2xx4.00260)xx931.5=22.4MeV`
The energy release per nucleon is 22.4/8 = 2.8 MeV. This is three times as much as is released in fission of uranium : 200/235 = 0.85 MeV per nucleon.