A normal man marries a woman who is a carrier for colour blindness. What will be the phenotypes of the children born to them? Depict the phenotypes through a possible cross.

Explanation

To solve the problem of determining the phenotypes of the children born to a normal man and a woman who is a carrier for color blindness, we can follow these steps:

### Step 1: Understand the Genetic Basis of Color Blindness
Color blindness is a sex-linked recessive trait located on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).

### Step 2: Determine the Genotypes of the Parents
- The normal man has a normal X chromosome and a Y chromosome. His genotype is represented as **X^N Y** (where X^N denotes the normal X chromosome).
- The woman is a carrier for color blindness. This means she has one normal X chromosome and one affected X chromosome. Her genotype is represented as **X^N X^c** (where X^c denotes the X chromosome carrying the color blindness allele).
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