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A dihybrid for qualitative trait is cros...

A dihybrid for qualitative trait is crossed with homozygous recessive individual of its type, the phenotypic ratio is

A

`1:2:1`

B

`3:1`

C

` 1:1:1:1`

D

`9:3:3:1`

Text Solution

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The correct Answer is:
To solve the question about the phenotypic ratio resulting from a dihybrid cross with a homozygous recessive individual, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Cross**: - A dihybrid organism has two traits, each with two alleles. For example, let's denote the traits as R (dominant) and r (recessive) for the first trait, and Y (dominant) and y (recessive) for the second trait. - The dihybrid organism can be represented as RrYy. - The homozygous recessive individual will be represented as rryy. 2. **Set Up the Gametes**: - The dihybrid organism (RrYy) can produce four types of gametes: RY, Ry, rY, and ry. - The homozygous recessive individual (rryy) can only produce one type of gamete: ry. 3. **Perform the Cross**: - When we cross RrYy with rryy, we can set up a Punnett square to visualize the offspring. - The gametes from RrYy (RY, Ry, rY, ry) will be placed on one side, and the gametes from rryy (ry) will be placed on the other side. 4. **Fill in the Punnett Square**: - The combinations will be: - RY x ry = RrYy (Round and Yellow) - Ry x ry = Rryy (Round and Green) - rY x ry = rrYy (Wrinkled and Yellow) - ry x ry = rryy (Wrinkled and Green) 5. **Determine the Phenotypes**: - From the combinations, we can identify the phenotypes: - 1 RrYy (Round and Yellow) - 1 Rryy (Round and Green) - 1 rrYy (Wrinkled and Yellow) - 1 rryy (Wrinkled and Green) 6. **Calculate the Phenotypic Ratio**: - The resulting phenotypic ratio from the cross is: - Round and Yellow : Round and Green : Wrinkled and Yellow : Wrinkled and Green - This gives us a ratio of 1:1:1:1. ### Final Answer: The phenotypic ratio of the offspring from this dihybrid cross with a homozygous recessive individual is **1:1:1:1**.
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Knowledge Check

  • A dihybrid for qualitative trait is crossed with homozygous recessive individual of its type, the phenotype ratio is:

    A
    `1:2:1`
    B
    `3:1`
    C
    `1:1:1:1`
    D
    `9:7`
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