The weight of a body at earth's surface is W. At a depth half way to the centre of earth it will weight

The weight of a body at earth's surface is W. At a depth halfway to the centre of the earth , it will be (assuming uniform density in the earth )

The weight of a body at the poles is greater than the weight at the equator. Is it the actual weight or the apparent weight we are talking about? Does your answer depend on whether only the earth's rotation is taken into account or the flattening of the earth at the poles is also taken into account?

What is the weight of a 70 kg body on the surface of a planet mass is 1/7 th that of earth and radius is is half of earth ?

A body is taken to a height equal to radius of earth and then to a depth equal to radius of earth. What will be its weight in each case ?

Weight fo a body of a mass m decreases by 1% when it is raised to height h above the earth's surface. If the body is taken to depth h in a mine, change in its weight is

Weight fo a body of a mass m decreases by 1% when it is raised to height h above the earth's surface. If the body is taken to depth h in a mine, change in its weight is

The ratio of the weights of a body on the Earth's surface to that on the surface of a planet is 9 : 4 . The mass of the planet is (1)/(9) th of that of the Earth, what is the radius of the planet ? (Tale the planets to have the same mass density).

Assuming earth to be a sphere of uniform mass density, how much would a body weigh half way down the centre of the earth, if it weighed 100 N on the surface ?

Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighd 250 N on the surface ?

The height above the earth s surface at which the weight of a person becomes 1/4th of his weight on the surface of earth is (R is the radius of earth)