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From 200 mg of CO(2),10^(21) molecules a...

From 200 mg of `CO_(2),10^(21)` molecules are removed. How many moles of `CO_(2)` are left ?

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Total no. Of moles of `CO_(2) = ("wt.in g")/("mol. Wt")`
`=0.2/44 =0.00454`
No. Of moles removed `=(10^(21))/(6.022 xx 10^(23)) = 0.00166`
No. Of moles of `CO_(2)` left `=0.00454 - 0.00166=0.00288`
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