How many grams of `CaWO_4` would contain the same mass of tungsten that is present in 569 g of `FeWO_4`? (W = 184)

Explanation

To solve the problem of how many grams of `CaWO_4` would contain the same mass of tungsten that is present in 569 g of `FeWO_4`, we can follow these steps:

### Step 1: Calculate the molar mass of `FeWO_4`
The molar mass of `FeWO_4` can be calculated by adding the atomic masses of its constituent elements:
- Iron (Fe): 56 g/mol
- Tungsten (W): 184 g/mol
- Oxygen (O): 16 g/mol (and there are 4 oxygen atoms)

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