The enzyme carbonic anhydrase catalyses the hydration of `CO_(2)`. This reaction: `CO_(2) + H_(2) to H_(2)CO_(3)`, is involved in the transfer of `CO_(2)` from tissues to the lungs via the bloodstream. One enzyme molecule hydrates `10^6` molecules of `CO_2` per second. How many kg of `CO_2` are hydrated in one hour in one litre by `1 xx 10^(6)` M enzyme?

Answer

To solve the problem, we need to calculate how many kilograms of CO2 are hydrated in one hour by 1 x 10^6 M of the enzyme carbonic anhydrase.

### Step-by-Step Solution:

1. **Determine the number of enzyme molecules in 1 liter:**
- The concentration of the enzyme is given as 1 x 10^6 M. This means there are 1 x 10^6 moles of enzyme in 1 liter.
- Using Avogadro's number (6.022 x 10^23 molecules/mol), we can find the number of enzyme molecules:
\[ \text{Number of enzyme molecules} = 1 \times 10^6 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mol} = 6.022 \times 10^{29} \, \text{molecules} \]

2. **Calculate the total number of CO2 molecules hydrated per second:**
- Each enzyme molecule hydrates 10^6 molecules of CO2 per second. Therefore, the total number of CO2 molecules hydrated per second by all enzyme molecules is:
\[ \text{Total CO2 molecules hydrated per second} = 6.022 \times 10^{29} \, \text{molecules} \times 10^6 \, \text{molecules/second} = 6.022 \times 10^{35} \, \text{molecules/second} \]

3. **Calculate the total number of CO2 molecules hydrated in one hour:**
- There are 3600 seconds in one hour, so the total number of CO2 molecules hydrated in one hour is:
\[ \text{Total CO2 molecules hydrated in one hour} = 6.022 \times 10^{35} \, \text{molecules/second} \times 3600 \, \text{seconds} = 2.169 \times 10^{39} \, \text{molecules} \]

4. **Convert the number of CO2 molecules to moles:**
- To convert molecules to moles, divide by Avogadro's number:
\[ \text{Total moles of CO2} = \frac{2.169 \times 10^{39} \, \text{molecules}}{6.022 \times 10^{23} \, \text{molecules/mol}} \approx 3.607 \times 10^{15} \, \text{moles} \]

5. **Calculate the mass of CO2 in kilograms:**
- The molar mass of CO2 is approximately 44 g/mol. To find the mass in kilograms:
\[ \text{Mass of CO2} = 3.607 \times 10^{15} \, \text{moles} \times 44 \, \text{g/mol} = 1.586 \times 10^{17} \, \text{grams} \]
- Convert grams to kilograms:
\[ \text{Mass of CO2 in kg} = \frac{1.586 \times 10^{17} \, \text{grams}}{1000} = 1.586 \times 10^{14} \, \text{kg} \]

### Final Answer:
The total mass of CO2 hydrated in one hour by 1 x 10^6 M enzyme in one liter is approximately **1.586 x 10^14 kg**.