5.6 litres of oxygen at NTP is equivalent to

Options

A. 1 mole
B. `1/2` mole
C. `1/4` mole
D. `1/8` mole

Answer

To find out how many moles of oxygen are present in 5.6 liters at Normal Temperature and Pressure (NTP), we can use the molar volume of a gas at NTP, which is 22.4 liters per mole.

### Step-by-Step Solution:

1. **Understand the Molar Volume**: At NTP (Normal Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters.

2. **Identify the Given Volume**: The problem states that we have 5.6 liters of oxygen gas.

3. **Use the Formula for Moles**: The number of moles (n) can be calculated using the formula:
\[ n = \frac{\text{Volume of gas (L)}}{\text{Molar volume (L/mol)}} \]
Here, the volume of the gas is 5.6 liters and the molar volume is 22.4 liters per mole.

4. **Substitute the Values**:
\[ n = \frac{5.6 \, \text{L}}{22.4 \, \text{L/mol}} \]

5. **Calculate the Number of Moles**:
\[ n = \frac{5.6}{22.4} = 0.25 \, \text{moles} \]

6. **Conclusion**: Therefore, 5.6 liters of oxygen at NTP is equivalent to 0.25 moles.

### Final Answer:
5.6 liters of oxygen at NTP is equivalent to 0.25 moles.

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