1 mole of a compound contains 1 mole of C and 2 moles of O. The molecular weight of the compound is

Options

A. 3
B. 12
C. 32
D. 44

Answer

To find the molecular weight of the compound that contains 1 mole of carbon (C) and 2 moles of oxygen (O), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the elements in the compound**:
The compound contains 1 mole of carbon (C) and 2 moles of oxygen (O).

2. **Write the empirical formula**:
Based on the given information, the empirical formula of the compound can be written as CO₂ (1 C and 2 O).

3. **Determine the atomic weights of the elements**:
- The atomic weight of carbon (C) is approximately 12 g/mol.
- The atomic weight of oxygen (O) is approximately 16 g/mol.

4. **Calculate the molecular weight of the compound**:
- For 1 mole of carbon:
\( 1 \text{ mole of C} = 1 \times 12 \text{ g/mol} = 12 \text{ g} \)
- For 2 moles of oxygen:
\( 2 \text{ moles of O} = 2 \times 16 \text{ g/mol} = 32 \text{ g} \)

5. **Add the weights together**:
- Total molecular weight = weight of carbon + weight of oxygen
- Total molecular weight = \( 12 \text{ g} + 32 \text{ g} = 44 \text{ g} \)

6. **Conclusion**:
The molecular weight of the compound CO₂ is 44 g/mol.

### Final Answer:
The molecular weight of the compound is 44 g/mol.

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