The weight of 1 mole of a gas of density 0.1784 g/L at NTP is

Options

A. 0.1748 g
B. 1 g
C. 4 g
D. cannot be calculated

Answer

To find the weight of 1 mole of a gas with a given density at Normal Temperature and Pressure (NTP), we can follow these steps:

### Step 1: Understand the given data
We are given:
- Density of the gas = 0.1784 g/L
- At NTP, 1 mole of any gas occupies a volume of 22.4 L.

### Step 2: Calculate the mass of 1 mole of the gas
We know that the mass of a gas can be calculated using the formula:
\[ \text{Mass} = \text{Density} \times \text{Volume} \]

Here, we need to find the mass of 1 mole of the gas, which occupies 22.4 L. Therefore, we can substitute the values into the formula:
\[ \text{Mass} = 0.1784 \, \text{g/L} \times 22.4 \, \text{L} \]

### Step 3: Perform the calculation
Now, we will perform the multiplication:
\[ \text{Mass} = 0.1784 \times 22.4 \]
\[ \text{Mass} = 3.99776 \, \text{g} \]

### Step 4: Round the answer
Since we typically round to a reasonable number of significant figures, we can round this to:
\[ \text{Mass} \approx 4 \, \text{g} \]

### Conclusion
The weight of 1 mole of the gas is approximately 4 grams.

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