Naturally occurring boron consists of two isotopes whose atomic weights are 10.01 and 11.01. The atomic weight of natural boron is 10.81. Calculate the percentage of each isotope in natural boron.

Explanation

To solve the problem of calculating the percentage of each isotope of boron in naturally occurring boron, we can follow these steps:

### Step 1: Define Variables
Let:
- \( x \) = percentage of boron isotope with atomic weight 10.01
- \( 100 - x \) = percentage of boron isotope with atomic weight 11.01

### Step 2: Set Up the Equation
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