Home
Class 12
CHEMISTRY
12 g of an element combines with 32 g of...

12 g of an element combines with 32 g of oxygen. What is the equivalent weight of the element if the equivalent weight of oxygen is 8?

Text Solution

AI Generated Solution

To find the equivalent weight of the element that combines with oxygen, we can use the concept of equivalent weights in chemical reactions. Here’s a step-by-step solution: ### Step 1: Understand the Concept of Equivalent Weight The equivalent weight of a substance is defined as the mass of that substance that combines with or displaces 1 mole of hydrogen or 8 grams of oxygen in a chemical reaction. ### Step 2: Write the Formula for Equivalent Weight The formula for equivalent weight (E) is given by: \[ E = \frac{\text{Weight of the substance}}{\text{Number of equivalents}} \] ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUIVALENCE

    RC MUKHERJEE|Exercise PROBLEMS|24 Videos
  • CHEMICAL EQUILIBRIUM

    RC MUKHERJEE|Exercise Objective Problems|57 Videos
  • CHEMICAL KINETICS

    RC MUKHERJEE|Exercise OBJECTIVE PROBLEMS |51 Videos

Similar Questions

Explore conceptually related problems

What is the equivalent weight of hydride of metal if equivalent weight of its oxide is 20?

0.1 g of metal combines with 46.6 mL of oxygen at STP . The equivalent weight of metal is

The equivalent weight of a metal is 12. What is the equivalent weight of its oxide?

The oxide of an element contains 67.67% of oxygen. Equivalent weight of the element is

An oxide of a metal contains 40% oxygen, by weight. What is the equivalent weight of the metal ?

RC MUKHERJEE-CHEMICAL EQUIVALENCE-PROBLEMS
  1. 12 g of an element combines with 32 g of oxygen. What is the equivalen...

    Text Solution

    |

  2. Fe forms two chlorides, FeCI2 and FeCI3. Does Fe have the same value o...

    Text Solution

    |

  3. The equivalent weight of a metal is 12. What is the equivalent weight ...

    Text Solution

    |

  4. 0.2 g of oxygen and 3.17 g of a halogen combine separately with the sa...

    Text Solution

    |

  5. Arsenic forms two oxides, one of which contains 65.2% and the other, 7...

    Text Solution

    |

  6. 1.80 g of a metal oxide required 833 mL of hydrogen at NTP to be reduc...

    Text Solution

    |

  7. A certain amount of a metal whose equivalent weight is 28, displaces 0...

    Text Solution

    |

  8. 9.44 g of a metal oxide is formed by the combination of 5 g of the met...

    Text Solution

    |

  9. 14.7 g of sulphuric acid was needed to dissolve 16.8 g of a metal. Cal...

    Text Solution

    |

  10. The salt Na(2) HPO(4) is formed when orthophosphoric acid is reacted w...

    Text Solution

    |

  11. 0.501 g of silver was dissolved in nitric acid and HCl was added to th...

    Text Solution

    |

  12. 5 g of zinc displaced 4.846 g of copper from a copper sulphate solutio...

    Text Solution

    |

  13. (i) What is the weight of sodium bromate and molarity of solution nece...

    Text Solution

    |

  14. 2 g of a metal when dissolved in nitric acid converted to its nitrate....

    Text Solution

    |

  15. 2 g of anhydrous BaCI2, present in a solution, was quantitatively conv...

    Text Solution

    |

  16. The chloride of a metal 'M' contains 47.23% of the metal. 1 g of this ...

    Text Solution

    |

  17. What weight of CuSO(4) . 5H(2) O must be taken to make 0.5 litre of 0....

    Text Solution

    |

  18. How many litres of SO(2) taken at NTP have to be passed through a solu...

    Text Solution

    |

  19. How many grams of H(2) S will react with 6.32 g of KMnO(4) to produce...

    Text Solution

    |

  20. One gram of the acid C(6) H(10) O(4) requires 0.768 g of KOH for compl...

    Text Solution

    |

  21. What is the weight of 1 gram-equivalent of the oxidising and the reduc...

    Text Solution

    |