Home
Class 12
CHEMISTRY
The equivalent weight of chlorine is 35....

The equivalent weight of chlorine is `35.5` and the equivalent weight of copper chloride is `99.5`. Find the formula of copper chloride if the atomic weight of Cu is `63.5`.

Text Solution

AI Generated Solution

To determine the formula of copper chloride (CuCl), we will use the information provided about the equivalent weights of chlorine and copper chloride, as well as the atomic weight of copper. ### Step-by-Step Solution: 1. **Identify the Given Information**: - Equivalent weight of chlorine (Cl) = 35.5 g/equiv - Equivalent weight of copper chloride (CuCl) = 99.5 g/equiv - Atomic weight of copper (Cu) = 63.5 g/mol ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUIVALENCE

    RC MUKHERJEE|Exercise PROBLEMS|24 Videos
  • CHEMICAL EQUILIBRIUM

    RC MUKHERJEE|Exercise Objective Problems|57 Videos
  • CHEMICAL KINETICS

    RC MUKHERJEE|Exercise OBJECTIVE PROBLEMS |51 Videos

Similar Questions

Explore conceptually related problems

The equivalent mass of chlorine is 35.5, and the molar mass of copper is 63.5. The equivalent mass of copper chloride is 99.0. Hence, formula of copper chloride is

Equivalent weight of a bivalent metal is 37.2 . The molecular weight of its chloride is

The equivalent weight of iron in ferric chloride is ( At.wt. of Fe = 55.8) -

The equivalent weight of divalent metal is 31.82 . The weight of a single atom is

RC MUKHERJEE-CHEMICAL EQUIVALENCE-PROBLEMS
  1. The equivalent weight of chlorine is 35.5 and the equivalent weight of...

    Text Solution

    |

  2. Fe forms two chlorides, FeCI2 and FeCI3. Does Fe have the same value o...

    Text Solution

    |

  3. The equivalent weight of a metal is 12. What is the equivalent weight ...

    Text Solution

    |

  4. 0.2 g of oxygen and 3.17 g of a halogen combine separately with the sa...

    Text Solution

    |

  5. Arsenic forms two oxides, one of which contains 65.2% and the other, 7...

    Text Solution

    |

  6. 1.80 g of a metal oxide required 833 mL of hydrogen at NTP to be reduc...

    Text Solution

    |

  7. A certain amount of a metal whose equivalent weight is 28, displaces 0...

    Text Solution

    |

  8. 9.44 g of a metal oxide is formed by the combination of 5 g of the met...

    Text Solution

    |

  9. 14.7 g of sulphuric acid was needed to dissolve 16.8 g of a metal. Cal...

    Text Solution

    |

  10. The salt Na(2) HPO(4) is formed when orthophosphoric acid is reacted w...

    Text Solution

    |

  11. 0.501 g of silver was dissolved in nitric acid and HCl was added to th...

    Text Solution

    |

  12. 5 g of zinc displaced 4.846 g of copper from a copper sulphate solutio...

    Text Solution

    |

  13. (i) What is the weight of sodium bromate and molarity of solution nece...

    Text Solution

    |

  14. 2 g of a metal when dissolved in nitric acid converted to its nitrate....

    Text Solution

    |

  15. 2 g of anhydrous BaCI2, present in a solution, was quantitatively conv...

    Text Solution

    |

  16. The chloride of a metal 'M' contains 47.23% of the metal. 1 g of this ...

    Text Solution

    |

  17. What weight of CuSO(4) . 5H(2) O must be taken to make 0.5 litre of 0....

    Text Solution

    |

  18. How many litres of SO(2) taken at NTP have to be passed through a solu...

    Text Solution

    |

  19. How many grams of H(2) S will react with 6.32 g of KMnO(4) to produce...

    Text Solution

    |

  20. One gram of the acid C(6) H(10) O(4) requires 0.768 g of KOH for compl...

    Text Solution

    |

  21. What is the weight of 1 gram-equivalent of the oxidising and the reduc...

    Text Solution

    |