0.501 g of silver was dissolved in nitric acid and HCl was added to this solution, AgCI so formed weighed 0.6655 g. If the equivalent weight of chlorine is 35.5, what will be the equivalent weight of silver?

Explanation

To solve the problem step by step, we will follow the principles of stoichiometry and the concept of equivalent weight.

### Step 1: Understand the Reaction
When silver (Ag) is dissolved in nitric acid (HNO3) and hydrochloric acid (HCl) is added, silver chloride (AgCl) is formed. The reaction can be represented as:
\[ \text{Ag} + \text{Cl}^- \rightarrow \text{AgCl} \]

### Step 2: Calculate the Equivalent Weight of AgCl
The equivalent weight of a compound can be calculated using the formula:
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