What weight of `CuSO_(4) . 5H_(2) O` must be taken to make `0.5` litre of `0.01` M `Cu(II)` ion solution?

Explanation

To find the weight of `CuSO4 . 5H2O` needed to prepare a `0.5` litre solution of `0.01 M` `Cu(II)` ions, we can follow these steps:

### Step 1: Calculate the number of moles of `Cu(II)` ions required.
The formula to calculate the number of moles is:
\[ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} \]
Given:
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