One gram of the acid `C_(6) H_(10) O_(4)` requires `0.768` g of `KOH` for complete neutralisation. How many neutralisable hydrogen atoms are in this molecule?

Explanation

To solve the problem, we need to determine how many neutralizable hydrogen atoms are present in the molecule of the acid \( C_6H_{10}O_4 \). This can be done by calculating the n-factor of the acid, which represents the number of hydrogen ions (\( H^+ \)) that can be released by one molecule of the acid during neutralization.

### Step-by-Step Solution:

1. **Identify the Given Information**:
- Mass of the acid (\( C_6H_{10}O_4 \)) = 1 g
- Mass of \( KOH \) used for neutralization = 0.768 g

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