What is the weight of 1 gram-equivalent of the oxidising and the reducing agent in the following reaction?
`5Zn + V_(2) O_(5) to 5 ZnO+ 2 V" "
`(V = 50.94, Zn = 65.38 and O = 16)`

Explanation

To find the weight of 1 gram-equivalent of the oxidizing and reducing agents in the reaction:

\[ 5 \text{Zn} + \text{V}_2\text{O}_5 \rightarrow 5 \text{ZnO} + 2 \text{V} \]

we will follow these steps:

### Step 1: Identify the Oxidizing and Reducing Agents
- **Zinc (Zn)** is oxidized from an oxidation state of 0 to +2, indicating it is a reducing agent.
- **Vanadium in V2O5** is reduced from +5 to 0, indicating it is an oxidizing agent.

### Step 2: Determine the Change in Oxidation States
- For **Zinc (Zn)**:
- Change in oxidation state = 0 to +2 = +2
- For **Vanadium (V)** in V2O5:
- Change in oxidation state = +5 to 0 = -5

### Step 3: Calculate the n-factor
- The n-factor is the total change in oxidation number per mole of the substance.
- For **Zinc (Zn)**:
- n-factor = 2 (since it changes from 0 to +2)
- For **Vanadium (V)** in V2O5:
- n-factor = 5 (for each vanadium atom, and there are 2 vanadium atoms in V2O5, so total = 5 * 2 = 10)

### Step 4: Calculate the Molecular Weights
- Molecular weight of **Zinc (Zn)** = 65.38 g/mol
- Molecular weight of **Vanadium Pentoxide (V2O5)**:
- V: 50.94 g/mol (2 atoms) = 2 * 50.94 = 101.88 g/mol
- O: 16 g/mol (5 atoms) = 5 * 16 = 80 g/mol
- Total for V2O5 = 101.88 + 80 = 181.88 g/mol

### Step 5: Calculate the Weight of 1 Gram-Equivalent
- **For Zinc (Zn)**:
- Gram equivalent = moles × n-factor
- 1 gram equivalent = 1/n-factor
- Moles of Zn for 1 gram equivalent = 1/2 = 0.5 moles
- Weight of 1 gram equivalent of Zn = moles × molecular weight = 0.5 × 65.38 = 32.69 g

- **For Vanadium Pentoxide (V2O5)**:
- Gram equivalent = moles × n-factor
- 1 gram equivalent = 1/n-factor
- Moles of V2O5 for 1 gram equivalent = 1/10 = 0.1 moles
- Weight of 1 gram equivalent of V2O5 = moles × molecular weight = 0.1 × 181.88 = 18.19 g

### Final Answers
- Weight of 1 gram-equivalent of Zinc (Zn) = **32.69 g**
- Weight of 1 gram-equivalent of Vanadium Pentoxide (V2O5) = **18.19 g**