Calculate the work of an isothermal reversible expansion of three moles of water vapour from `5.0 xx 10^4` to `2.0 xx 10^4` Pa at 330 K.

Explanation

To calculate the work done during an isothermal reversible expansion of three moles of water vapor from \(5.0 \times 10^4\) Pa to \(2.0 \times 10^4\) Pa at a temperature of 330 K, we can use the formula for work done in an isothermal reversible process:

\[ W = -2.303 \, nRT \log \left( \frac{P_1}{P_2} \right) \]

### Step-by-Step Solution:

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