If the vapour pressure of pure liquids A and B are 300 mm and 800 mmHg at `75^@C` , calculate the composition of the mixture such that it boils at `75^@C`. Find the composition of the vapour phase.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Understand the Problem
We need to find the composition of a mixture of two liquids A and B that boils at 75°C, given their vapor pressures at this temperature. The vapor pressures are:
- \( P^0_A = 300 \, \text{mmHg} \)
- \( P^0_B = 800 \, \text{mmHg} \)

### Step 2: Use Raoult's Law
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