100 mL of 0.6 N `CuSO_4` solution is electrolysed between two Pt electrodes till the concentration in the residual liquid is 0.1 N when a steady current of 5.0 amp is used. How long should the current be passed to get the said change?

Explanation

To solve the problem step-by-step, we will follow the process of calculating the time required for the electrolysis of the given copper sulfate (CuSO4) solution.

### Step 1: Determine the initial and final normality of the solution.
- **Initial Normality (N1)** = 0.6 N
- **Final Normality (N2)** = 0.1 N

### Step 2: Calculate the volume of the solution.
- **Volume (V)** = 100 mL = 0.1 L
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