The reaction `Cl_2(g) + S_2O_3^(2-) to SO_4^(2-) +Cl^(-)` is to be carried out in alkaline solution. Starting with 0.15 mole of `Cl_2`, 0.01 mole of `S_2O_3^(2-)` and 0.30 mole of `OH^-` . How many mole of `O^-` will be left in the solution after the reaction is complete? Assume that no other reaction takes place.

Explanation

`4Cl_2 + S_2O_3^(2-) + 10OH^(-) to 2SO_4^(2-) + 8Cl^(-) + 5H_2O`
0.2mole