A beaker containing 0.01 mole of `C_12H_22O_11` in 100 g of `H_2O` and a beaker containing 0.02 mole of `C_12H_22O_11` in 100 g of `H_2O` are placed in a chamber and allowed to equilibrate. What is the concentration (mole fraction) of `C_11H_22O_11` in the resulting solutions?

Explanation

To find the mole fraction of sucrose (C₁₂H₂₂O₁₁) in the resulting solutions after mixing, we can follow these steps:

### Step 1: Calculate the total moles of sucrose
We have two beakers:
- Beaker 1: 0.01 moles of sucrose
- Beaker 2: 0.02 moles of sucrose

**Total moles of sucrose** = moles from Beaker 1 + moles from Beaker 2
...