Calculate the equilibrium constant at `25^@`C for the reaction:
`2Fe^(3+) + 2I^(-) = 2Fe^(2+) + I_2`
Given that `E^@ Fe^(3+) , Fe^(2+) = 0.77 V, E^@ I_2, I^(-) = 0.536V`

Explanation

To calculate the equilibrium constant \( K_c \) for the reaction:

\[ 2 \text{Fe}^{3+} + 2 \text{I}^- \rightleftharpoons 2 \text{Fe}^{2+} + \text{I}_2 \]

at \( 25^\circ C \), we will follow these steps:

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