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For the galvanic cell Ag | AgCl (s)...

For the galvanic cell
`Ag | AgCl (s), KCl(0.2 M)||KBr(0.001 M), AgBr(s)|Ag`,
calculate the emf generated and assign correct polarity to each electrode for a spontaneous process after taking into account the cell reaction at `25^@C`.
` K_(sp)(AgCl) = 1.8 xx 10^(-10), K_(sp)(AgBr) = 3.3 xx10^(-13)`

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Calculate `[Ag^+]` from `K_(sp)` values for both the half cells and then calculate
`E_("cell") ` for `Ag|Ag^(+) (c_1) | Ag^(+) (c_2) | Ag `
0.037V
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