The vapour pressure of a 5% solution of a nonvolatile organic substance in water at 373 K is `0.9935 xx 10^5Nm^(-1)` . Calculate the molecular mass of the solute `(1 atm= 1.0132 xx 10^5 Nm^(-2))`

Explanation

To calculate the molecular mass of the solute in a 5% solution of a nonvolatile organic substance in water, we can follow these steps:

### Step 1: Identify the given values
- Vapor pressure of the solution (P_s) = \(0.9935 \times 10^5 \, \text{N/m}^2\)
- Vapor pressure of pure water (P_0) at 373 K = \(1.0132 \times 10^5 \, \text{N/m}^2\)
- Mass of solute = 5 g (since it is a 5% solution)
- Mass of solvent (water) = 95 g (since the total mass of the solution is 100 g)

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