One gram of commercial `AgNO_3` is dissolved in 50 mL of water. It is treated with 50 mL of a KI solution. The silver iodide thus precipitated is filtered off. Excess of KI in the filtrate is titrated with (M/10) `KIO_3` solution in the presence of 6 M HCl till all I ions are converted into ICl. It requires 50 mL of (M/10)` KIO_3` solution. 20 mL of the same stock solution of KI requires 30 mL of (M/10) `KIO_3` under similar conditions. Calculate the percentage of `AgNO_3` in the sample.

Explanation

Reaction : `KIO_3 +2KI + 6HCl = 3ICl + 3H_2O `
85%