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The cathodic reaction of a Zn - MnO2 d...

The cathodic reaction of a `Zn - MnO_2` dry cell is represented as
`2 MnO_2(s) + Zn^(2+) + 2e = Zn MnO_4(s)` .
If there is 8.0 g `MnO_2` present in the cathodic chamber, how long will the cell function to supply `4 xx 10^(-3)` ampere of current?

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`(4 xx 10^(-3) xx t(s))/(96500) = 8/87 , E_(MnO_2) = 87`
25.67 days
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