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Hot carbon reacts with steam to produce an equimolar rnixture of CO(g) and `H_2(g)` known as water gas. What is the energy released as water gas is used as fuel?
`CO(g) +1/2O_2(g) to CO_2(g) , Delta H = -282.985kJ`
`H_2(g) + 1/2 O_2(g) to H_2O(g), Delta H = -241.818 kJ`

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To find the energy released when water gas (a mixture of CO and H₂) is used as fuel, we need to consider the combustion reactions of both components (CO and H₂) and their respective enthalpy changes. ### Step-by-Step Solution: 1. **Identify the Reactions**: - The combustion of carbon monoxide (CO): \[ \text{CO(g)} + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}_2(g) \quad \Delta H = -282.985 \text{ kJ} ...
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The enthalpy of vaporisation of liquid water using the data H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) , DeltaH=-285.77 kJ//mol H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g) , DeltaH=-241.84 kJ//mol

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Equal volumes of C_(2)H_(2) and H_(2) are combusted under identical conditons. The ratio of evolved in i.e. for C_(2)H_(2) and H_(2) is: H_(2)(g) + 1/2O_(2) (g) to H_(2)O(g), DeltaH=-241.8 kJ C_(2)H_(2)(g) + 21/2O_(2)(g) to 2CO_(2)(g) + H_(2)O(g), DeltaH = -1300 kJ

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