Calculate the mole fraction of a benzene-toluene liquid solution that is in equilibrium with a vapour phase that contains 62 mole % `C_6H_6` . Vapour pressures of benzene and toluene at `25^@C` are 95.1 mm and 28.4 mm respectively.

Explanation

To solve the problem of calculating the mole fraction of a benzene-toluene liquid solution that is in equilibrium with a vapor phase containing 62 mole % benzene, we will apply Raoult's Law. Here’s a step-by-step solution:

### Step 1: Identify Given Data
- Mole fraction of benzene in vapor phase, \( Y_{C_6H_6} = 0.62 \)
- Vapor pressure of benzene, \( P^0_{C_6H_6} = 95.1 \, \text{mmHg} \)
- Vapor pressure of toluene, \( P^0_{C_7H_8} = 28.4 \, \text{mmHg} \)

### Step 2: Calculate the Total Pressure
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