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The thermochemical equation for the diss...

The thermochemical equation for the dissociation of hydrogen gas into atoms may be written as:
`H_2 to 2H, Delta H =436 kJ`
What is the ratio of the energy yield on combustion of hydrogen atoms to steam to the yield on combustion of an equal mass of hydrogen molecule to steam? Heat of formation of `H_2O(g)` is `- 241.81 kJ "mole"^(-1)`

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The thermochemical equation for the dissociation of hydrogen gas into atoms may be written as H_2 to 2H , Delta H = 436 kJ What is the ratio of the energy yield on combustion of hydrogen atoms to steam to the yield on combustion of an equal mass of hydrogen molecules to steam? DeltaH_("combustion") for H_2 = -241.81 kJ .

What is the ratop of the enthalpy yield on combustion of hydrogen of hydrogen atoms to steam to the yield on combustion of an equal mass of hydrogen molecules to steam ? Given: H_(2) (g) + (1)/(2) O_(2) (g) rarr H_(2) O (g) , Delta H = -242 kJ B.E. (H - H) = 436 kJ

Calculated the energy required to excite one litre of hydrogen gas at 1atm and 298K to the first excited state of atomic hydorgen. The enegry for the dissociation of H-H bond is 436 kJ mol^(-1) .

Teo atoms of hydrogen combine to form a molecule of hydrogen gas, the energy of the H_(2) molecule is :

Oxygen atoms and hydrogen atoms in H_2O_2 are collinear.

What is the charge in mass when 2 mole of hydroghen atoms combine to form 1 mole fo H_(2) molecule if: 2H rarr H_(2), Delta E = -436 kJ ? Comment on the result.

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