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Calculate DeltaHf^@ for chloride ion fro...

Calculate `DeltaH_f^@` for chloride ion from the following data
`1/2 H_2(g) + 1/2 Cl_2(g) to HCl (g) , Delta H_f^@ = -92.4kJ`
`HCl(g) + xH_2O to H^(+)(aq) + Cl^(-) (aq), Delta H_(298) = -74.8kJ`
`Delta H_f^@ [H^(+) (aq) ] = 0.0kJ`

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To calculate the enthalpy of formation (\( \Delta H_f^@ \)) for the chloride ion (\( Cl^- \)), we will use the provided thermochemical equations and their corresponding enthalpy changes. ### Step-by-Step Solution: 1. **Write the first reaction**: \[ \frac{1}{2} H_2(g) + \frac{1}{2} Cl_2(g) \rightarrow HCl(g) \quad \Delta H_f^@ = -92.4 \, \text{kJ} \] ...
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Calculate Delta H^(@)._(f) for chloride ion from the following data : (1)/(2)H_(2)(g) + (1)/(2)Cl_(2)(g) rarr HCI(g), Delta H^(@)._(f) = -92.4 kJ HCI(g) + nH_(2)O rarr H^(+) (aq) + CI^(-)(aq), Delta H^(@) = - 74.8 kJ Delta H^(@)._(f) H^(+) (aq) = 0.0 kJ

Calculate Delta_(f)H^(@) for chloride ion from the following data: 1/2H_(2)(g) + 1/2CI_(2)(g) to HCI(g) Delta_(f)H^(@) = -92.8 kJ mol^(-1) HCI(g) + H_(2)O to H_(3)O^(+)(aq) + CI^(-)(aq) Delta_(diss) H^(@) = - 75.2 kJ mol^(-1) .

Calculate DeltaH_(f)^(@) for chloride ion from the following data : (1)/(2)H_(2(g))+(1)/(2)Cl_(2(g))rarr HCl_((g)),DeltaH_(f)^(@)=-92.4kJ HCl_((g))+nH_(2)O rarr H_((aq.))^(+)+Cl_((aq.))^(-),DeltaH^(@)=-74.8kJ DeltaH_(f)^(@) H_((aq.))^(+)=0.0kJ

Calculate the enthalpy of formation of anhydrous aluminium chloride, Al_(2)Cl_(6) from the following data : (i) 2Al(s) + 6HCl (aq) to Al_(2)Cl_(6) (aq) + 3H_(2)(g), Delta_(r)H^(@) = -1004.0 kJ (ii) H_(2)(g) + Cl_(2)(aq) to 2HCl(g) , Delta_(r)H^(@) = -183.9 kJ , Delta_(r)H^(@) = -183.9 kJ (iii) HCl(g) + aq to HCl(aq), Delta_(r)H^(@) = -73.2 kJ Al_(2)Cl_(6)(s) + aq to Al_(2) Cl_(2)(aq) , Delta_(r)H^(@) = -643.0 kJ

Calculate the enthalpy of formation of KOH(s) from the following data : K(s) + H_(2)O(l) + (aq) to KOH(aq) + 1/2 H_(2)(g) Delta_(r)H^(@) = -200.8 kJ H_(2)(g) + 1/2 O_(2)(g) to H_(2)O(l) Delta_(r)H^(@) = - 286.3 kJ KOH(s) + (aq) to KOH(aq) Delta_(r)H^(@) = - 58.6 kJ

Calculate the enthalpy of formation of methane from the following data : C(s) + O_(2)(g) to CO_(2)(g) Delta_(r)H^(@) = -393.5 kJ 2H_(2)(g) + O_(2)(g) to 2H_(2)O(l) Delta_(r)H^(@) = -571.8 kJ CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l) Delta_(r)H^(@) = -890.3 kJ

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