Home
Class 12
CHEMISTRY
Air was drawn through a solution contain...

Air was drawn through a solution containing 38 g of solute in 100 g of water, and then through water. The loss of weight of water was 0.0551 g and the total weight of water absorbed in sulphuric acid tube was 2.2117 g. Find the molecular weight of the dissolved substance

Text Solution

Verified by Experts

Raoult.s law: lowering of VP / VP of solvent = mole fraction of solute
`(0.0551)/(2.2117) = (38//M)/
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS OBJECTIVE QUESTIONS

    RC MUKHERJEE|Exercise MCQ|277 Videos
  • MOLECULAR WEIGHT

    RC MUKHERJEE|Exercise PROBLEMS |12 Videos

Similar Questions

Explore conceptually related problems

Dry air was passed successively through a solution of 5g of a solute in 180g of water and then through pure water and then through pure water. The loss in weight of solution was 2.5g and that of pure solvent 0.04g . The molecular weight of the solute is:

Dry air was successively passed through a solution of 5g solute in 80g water and then through pure water. The loss in weight of solution was 2.5g and that of pure water was 0.04g . What is mol. wt. of solute ?

Dry air was suvvessively passed through a solution of 5 g solute in 80 g water and then through pure water. The loss in weight of solution was 2.5 g and that of pure water was 0.04 g . What is mol.wt. of solute?

Dry air was passed successively through a solution of 5 g of a solute in 180 g water and then through pure water. The loss in weight of solutionwas 250 g and that of pure solvent 0.04 g . The molecular weight of the solute is

Dry air was passed successively through solution of 5g of a solute in 180g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04g . The molecualr weight of the solute is:

RC MUKHERJEE-MISCELLANEOUS PROBLEMS FOR REVISION-SUBJECTIVE TYPE QUESTIONS
  1. The vapour pressure of heptane and toluene at 50^@C are 141 mm and 93...

    Text Solution

    |

  2. Mixture of two liquids A and B is placed in cylinder containing piston...

    Text Solution

    |

  3. Air was drawn through a solution containing 38 g of solute in 100 g of...

    Text Solution

    |

  4. A mixture of nitrogen and hydrogen in a proportion of 1 : 3 by volume ...

    Text Solution

    |

  5. The equilibrium constant for the reaction H2(g) + I2(g) iff 2HI(g...

    Text Solution

    |

  6. At 21.5^@C and a total pressure of 0.0787 atm, N2O4 is 48.3% dissocia...

    Text Solution

    |

  7. Calculate the electron affinity of chlorine from the given data:

    Text Solution

    |

  8. A gas expands from a volume of 3.0 dm^(3) to 5.0 dm^(3) against a cons...

    Text Solution

    |

  9. Determine the enthalpy of the reaction C3H8(g) + H2(g) to C2H6(g)...

    Text Solution

    |

  10. A cylindrical tube of length 30 cm is partitioned by a tight-fitting s...

    Text Solution

    |

  11. By how many folds the temperature of a gas would increase when the rms...

    Text Solution

    |

  12. The order of a reaction, A + 2B to C , is 1 and 2 with respect to A an...

    Text Solution

    |

  13. The activation energy for a first-order reaction is 104.5 kJ/mole and ...

    Text Solution

    |

  14. The activation energy of a certain uncatalysed reaction at 300 K is 76...

    Text Solution

    |

  15. Two reactions of the same order have equal pre-exponential factors, bu...

    Text Solution

    |

  16. Two bulbs A and B of equal capacity are filled with He and SO(2), resp...

    Text Solution

    |

  17. Two flacks of equal volume connected by a narrow tube of negligible vo...

    Text Solution

    |

  18. The standard electrode potential of a standard hydrogen half cell is 0...

    Text Solution

    |

  19. The potential for the reaction O2 (g) + 4H^(+) + 4e = 2H2O (l) ...

    Text Solution

    |

  20. Calculate the solubility product of the reaction Fe(OH)3 = Fe^(3+...

    Text Solution

    |