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Determine the enthalpy of the reaction ...

Determine the enthalpy of the reaction
`C_3H_8(g) + H_2(g) to C_2H_6(g) + Ch_4(g) at 25^@C`
using the given heat of combustion values under standard conditions.

The standard heat of formation of `C_2H_2(g)` is - 103.8 kJ/mole.

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`-55.7kJ`
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The enthalpy change of the reaction C_3H_8(g)+H_2(g) rarr C_2H_6(g)+CH_4(g) , at 25^@ , will be Given that: heat of combustion values under standard condition (The standard heat of formation of C_3H_8(g) is -103.8kJ/mol)

Determine the enthalpy change of the reaction. C_(3)H_(5) (g) + H_(2) (g) rarr C_(2)H_(6) (g) + CH_(4) (g) at 25^(@)C , using the given heat of combustion value under standard conditions: Compound H_(2) (g) CH_(4) (g) C_(2) H_(6) (g) C (graphite) Delta H^(@) (kJ//mol) -285.8 =890.0 - 1560.0 -393.5 The standard heat of formation of C_(3)H_(8) (g) is -103.8 kJ//mol

Determine enthalpy change for, D_(3)H_(8(g))+H_(2(g))rarr C_(2)H_(6(g))+CH_(4(g)) at 25^(@)C using heat of combustion values under standard condition. {:(Compounds,H_(2(g)),CH_(4(g)),C_(2)H_(6(g)),C_((Graph ite))),(DeltaH^(@)i n kJ//mol,-285.8,-890.0,-1560.0,-393.5):} The standard heat of formation of C_(3)H_(8(g)) is -103.8 kJ mol^(-1) .

The enthalpy change for the reaction C_(3)H_(8)(g)+H_(2)(g) rarr C_(2)H_(6)(g)+CH_(4)(g) at 25^(@)C is -55.7 kJ/mol. Calculate the enthalpy of combustion of C_(2)H_(6)(g) . The enthalpy of combustion of H_(2) , & CH_(4) are -285.8 & -890.0 kJ/mol respectively. enthalpy of combustion of propane is -2220" kJ mol"^(-1) .

The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :

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