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The solubility product of AgCl is 1.0xx1...

The solubility product of AgCl is `1.0xx10^(-10)` . The equilibrium constant of the reaction
`AgCl(s) + Br^(-) iff AgBr(s) + Cl^(-)`
is `2 xx 10^2` and that of the reaction
`2AgBr(s) + S^(2-) iff Ag_2S(s) + 2Br^(-)`
is `1.6 xx 10^24` . Calculate `K_(sp)` of `Ag_2S`

Text Solution

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`1.56 xx 10^(-49)`
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