How much water should be added to 10 g of acetic acid to give a hydrogen-ion concentration equal to `1xx10^(-3)M? K_a (CH_2COOH) = 1.8 xx 10^(-5)`.

Explanation

To solve the problem of how much water should be added to 10 g of acetic acid to achieve a hydrogen-ion concentration of \(1 \times 10^{-3} \, M\), we will follow these steps:

### Step 1: Calculate the number of moles of acetic acid
The molecular weight of acetic acid (\(CH_3COOH\)) is approximately 60 g/mol.

\[ \text{Moles of acetic acid} = \frac{\text{mass}}{\text{molecular weight}} = \frac{10 \, g}{60 \, g/mol} = \frac{1}{6} \, mol \approx 0.1667 \, mol \]
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