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Consider the equilibrium: LiCl - 3NH3(s)...

Consider the equilibrium: `LiCl - 3NH_3(s) = LiCl · NH_3(s) + 2NH_3(g)` with `K_p=9 atm^2` at `40^@C`. A 5-litre flask contains 0.1 mole of LiCl. `NH_3` . How many moles of NH, should be added to the flask at this temperature to drive the backward reaction practically to completion?

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To solve the problem, we need to analyze the equilibrium reaction and apply the equilibrium constant \( K_p \) to determine how many moles of \( NH_3 \) should be added to drive the backward reaction to completion. ### Step-by-Step Solution: 1. **Write the equilibrium expression**: The given equilibrium is: \[ LiCl \cdot 3NH_3(s) \rightleftharpoons LiCl \cdot NH_3(s) + 2NH_3(g) ...
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