`COF_2` gas passed over a catalyst at `1000^@C` comes to equilibrium:
`2 COF_2(g) iff CO_2(g) + CF_4(g)`
Analysis of the equilibrium mixture (after quick cooling to freeze the equilibrium) shows that 500 mL of equilibrium mixture (NTP) contains 300 mL (NTP) of `COF_2` and `CO_2` . Taking the total pressure to be 10 atm, calculate `K_p` .

Explanation

To solve the problem, we need to determine the equilibrium constant \( K_p \) for the reaction:

\[ 2 \text{COF}_2(g) \iff \text{CO}_2(g) + \text{CF}_4(g) \]

### Step-by-Step Solution:

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