The wavenumber of the first line in the Balmer series of hydrogen is `15200 cm^(-1)`. What is the wavenumber of the first line in the Balmer series of `Be^(3+) ?`

Explanation

To find the wavenumber of the first line in the Balmer series of \( \text{Be}^{3+} \), we can use the relationship between the wavenumber and the atomic number of the element. The wavenumber for the Balmer series can be expressed as:

\[ \bar{\nu} = RZ^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \]

where:
- \( \bar{\nu} \) is the wavenumber,
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