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For the equilibrium: NH4HS(s) = NH3(g) +...

For the equilibrium: `NH_4HS(s) = NH_3(g) + H_2S(g), K_p = 0.05 atm^2 ` at `20^@C`. If 0.06 role of solid `NH_4 HS` is placed in a 2.40-litre flask at `20^@C` , calculate the percentage of the solid decomposed under equilibrium.

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(a) 0.1089 (b) 0.19, 0.57 (c) 0.5672 g
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