Calculate `[SO_4^(2-) ]` in 0.15 M `H_2SO_4` solution if the first step of ionisation is complete and the second step `K_2 = 1.02 xx 10^(-2)`

Explanation

To calculate the concentration of \([SO_4^{2-}]\) in a 0.15 M \(H_2SO_4\) solution, we follow these steps:

### Step 1: Understand the Ionization of \(H_2SO_4\)
\(H_2SO_4\) is a strong acid that completely ionizes in its first step:
\[ H_2SO_4 \rightarrow H^+ + HSO_4^- \]
Since the first step is complete, the concentration of \(H^+\) and \(HSO_4^-\) will both be 0.15 M.
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