At what temperature would the average translational kinetic energy of gaseous hydrogen molecules equal the energy required to dissociate the molecules into atoms, i.e., 104 kcal per mole?

Explanation

To find the temperature at which the average translational kinetic energy of gaseous hydrogen molecules equals the energy required to dissociate the molecules into atoms (104 kcal per mole), we can follow these steps:

### Step 1: Understand the relationship between kinetic energy and temperature
The average translational kinetic energy (KE) of one mole of gas is given by the formula:
\[ KE = \frac{3}{2}RT \]
where \( R \) is the universal gas constant and \( T \) is the temperature in Kelvin.
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