Calculate the pH of a 0.005 M `Na_2 S` solution. `K_1` and `K_2` for `H_2S` are `1xx10^(-7)` and 1x `10^(-14)` respectively.

Explanation

To calculate the pH of a 0.005 M Na₂S solution, we need to follow these steps:

### Step 1: Identify the dissociation of Na₂S
Sodium sulfide (Na₂S) dissociates completely in water to give sodium ions (Na⁺) and sulfide ions (S²⁻):
\[ \text{Na}_2\text{S} \rightarrow 2 \text{Na}^+ + \text{S}^{2-} \]

### Step 2: Determine the concentration of S²⁻
Since Na₂S is a strong electrolyte, the concentration of sulfide ions (S²⁻) in the solution will be equal to the concentration of Na₂S:
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