What is the molarity of 4N `H_2SO_4` in the following reaction?
`8H^(+)+ H_2SO_4 + 8e^(-) to H_2S + 4H_2`

Explanation

To find the molarity of 4N \( H_2SO_4 \) in the given reaction, we can follow these steps:

### Step 1: Understand Normality and Valency Factor
Normality (N) is a measure of concentration equivalent to molarity (M) multiplied by the valency factor (n). The valency factor for sulfuric acid in this reaction can be determined by looking at the number of electrons transferred.

### Step 2: Identify the Valency Factor
In the given reaction:
\[ 8H^+ + H_2SO_4 + 8e^- \rightarrow H_2S + 4H_2 \]
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